Pi=3.14, nothing really to get so excited about. (in my opinion) LoL!

According to my physics teacher Pi=3. My teacher also claims that the only numbers ever used in physics are 0, 1, e, Pi, 5, and 10^x where x=any integer.

I didn't know about the 5, I've seen some 1/2, I suppose that is 5x10^0. Surely c comes in quite a bit as well, I mean isn't the SI stuff based upon it?

Ciaran

5 * 10^0 = 5

you meant 5 * 10^1

Actually I meant 10^-1, didn't I? 10^-1 is 0.1 I think.

Ciaran

5x10^0
=5x1
=5

Concerning the number 3, I think your teacher has pi confused with his IQ.

"Concerning the number 3, I think your teacher has pi confused with his IQ.
"

LOL.
At least its better then people spouting on and on over a subject that they don't know anything about.

Maybe that persons teacher only carries a certain number significant digits.

=)

On PI day '99 I found the poem at http://users.aol.com/s6sj7gt/mikerav.htm
It's called "Near a Raven" and it's a constricted poem about PI modeled after Poe, it's something to read with friends on Pi day!
Mike

So...Did anyone have any pi?

Jeez you people, do you not even read the article! The code that he presented will not work. The formula is wrong.
I modified the program above to make it better, so here it is. It is written in Ti-83 Basic.

:ClrDraw
:0->N:0->D
:-1->Xmin:1->Xmax
:-1->Ymin:1->Ymax
:Circle(0,0,1
:While 1
:rand*2-1->X
:rand*2-1->Y
:Pt-On(X,Y
:If sqrt(X^2+Y^2)<=1
:N+1->N
:D+1->D
:Text(0,0,(4N/D)
:End

And I don't think that this method is that good, it only gives pi after it runs for like 3 hours.

Ok, after running this program for exactly 26 minutes and 44.76 seconds, I arrived at the number
3.1453438
And as you all know, pi is:
3.1415927

So basically, it takes about 8 minutes to confirm one digit.
Although I must admit, this is pretty cool, I always wondered how you could calculate pi.

geese people.. this will give an EXACT answer:
****************************************
4(tan-1(1/2)+tan-1(1/3))
****************************************
the tan-1 is the arctangent or whatever

or 4*arctan 1

or 1/(sqrt(8)/9801*sum{n=0 to inf}((4n)!(1103 + 26390n)/(n!)^4(396^(4n))))
which gains 8 digits of precision with each term (can't write sigma notation here...)

This is even faster:

a[0] = sqrt(2); b[0]=0; c[0]=2+sqrt(2);

a[n+1] = (sqrt(a[n])+1/sqrt(a[n]))/2;
b[n+1] = sqrt(a[n])*((b[n]+1)/(a[n]+b[n]));
c[n+1] = c[n]*b[n+1]*(1+a[n+1])/(1+b[n+1]);

DOUBLES the number of correct decimals each iteration. Oh, pi is in c[n] btw.

MY GOD PEOPLE!! How the hell do you figure this out? I THINK I'M GOING INSANE!

Jimmy, are you sure this is the right information? When I run it, I get ungodly numbers.....

i would have put this one in there before, except i didn't think of using the square brackets :) multiplies by 4 each iteration:
a[0]=6-4sqrt(2)
y[0]=sqrt(2)-1
y[n+1]=(1-(1-y[n]^4)^.25) / (1+(1-y[n]^4)^.25)
a[n+1]=(1+y[n+1])^4*a[n] - 2^(2n+3)*y[n+1]*(1+y[n+1]+y[n+1]^2)

pi being a[n]. there's supposedly one that multiplies by 5 somewhere.
and, no i didn't just figure these out!! they're out of a book. some "s ramanujan" guy figured them out. i have no idea how.

one more thing... just think, in 15 years it'll be 3-14-15

Ive got an even faster method for calculating pi, but it is accurate to only about 9 decimal places.

the equation is:
2nd button
pi key

yes! the fastest method!

naw, that requires actually *finding* the calculator!

I'm just going to put three unrelated replies here:

To a post much farther up:
I actually did memorize pi to 69 digits, it's quite easy if you do it over a period of a couple weeks, for anybody interested, I also enjoy memorizing poetry, especially Poe's "The Raven". At the moment, I have the first seven stanzas memorized.

To the post two levels down:
pi = 3.14159265+
not 3.1415927

To the post just before this one(the one that I'm actually replying to):
It's not exact. It's only accurate to the calculator's accuracy. Okay,now everybody flame me about how geeky I am :)

If you do it on a calculator, you'll get an approximation, but the formula does give an exact answer.