Re: Calculus (Substitution)...

To: CALC-TI@LISTS.PPP.TI.COM
Subject: Re: Calculus (Substitution)...
From: Charlie Reno <creno@EN.COM>
Date: Fri, 13 Nov 1998 07:37:56 -0500
Comments: To: Bill Risher <billr1@MIDSOUTH.NET>
In-Reply-To: <3.0.6.32.19981112221738.00a2a8e0@mail.midsouth.net>
Reply-To: Charlie Reno <creno@EN.COM>

On Thu, 12 Nov 1998, Bill Risher wrote:

> At 09:48 PM 11/12/98 -0500, Thomas J. Hruska wrote:
> >Help!  I have an integral that I can't work either forward or backward.
> >
> >Here is the problem (S = integral sign):
> >
> >S (e^x - 3)^(1/2) dx
> >
> >
> >The problem states that I have to use substitution, so:
> >
Try:
  u^2 = e^x - 3

Now:
  2 u du  = e^x dx

and we get the problem to be

  s  u * 2u/(u^2+3)*du.

Take the 2 out front, collect/simplify, do long division, hope to get an
inverse tangent form anti derivative.

References:

Re: Calculus (Substitution)...

From: Bill Risher <billr1@MIDSOUTH.NET>

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