Re: TI-M: I think you're a weenie!!!
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Re: TI-M: I think you're a weenie!!!
> (1/3)x^3+x^2+C=(2/3)x^3+x^2+C
> take the derivitve
> x^2+2x=2x^2+2X
> divide by x
> x+2=2x+2
> cancel the 2's
> x=2x
hmmm if x=2x than x MUST be 0!
so then you divide by zero which gives you
infinity=infinity
> divide by x again
> 1=2
>
> There you go. It's all legal (like I said before:
> hopefully!!!) and it's
> NOT false math.
>
> Mark Hazard
>
>
>
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