Re: TI-M: TI-89 root question

To: ti-math@lists.ticalc.org
Subject: Re: TI-M: TI-89 root question
From: Andy Selle <aselle@ticalc.org>
Date: Wed, 7 Jun 2000 02:12:54 +0200 (MET DST)
In-Reply-To: <20000606211824.34340.qmail@hotmail.com>
Reply-To: ti-math@lists.ticalc.org


Yeah... the TI-89 doesn't have the nth root symbol in the MISC menu of
math like th TI-89.  The method you specify is the same as a^(1/n) =
a^(n^(-1)) = a^n^(-1) because ^ is highest prescedence and right
associative...(at least in standard arithmetic parsers, but I believe the
TI-89 follows this convention too)


--
Andy Selle <aselle@ticalc.org>
   Programming and System Administration, Survey Editor, Accounts Manager
   the ticalc.org project - http://www.ticalc.org/


On Tue, 6 Jun 2000, Robert Mohr wrote:

> 
> I don't know much about the TI-89, but I know how to get the nth root of a 
> number on the 86 in a couple of ways.
> 
> First, on the TI-86, there's a command that has a little "x" up high in the 
> first space, then a radical sign, and then you put the number in.  It should 
> look something like this:
> 
>                               ___
>              \/              /
>              /\             /
>                    __      /
>                      \    /
>                       \  /
>                        \/
> 
> You put 3 in fromt of that and 27 afterwards and it'll return 3.
> 
> And before I knew about that, i did this:
> 
> 27^3(-1)
> 
> Note:  the -1 is for inverse, not negative one.
> 
> 
> ----Original Message Follows----
> From: JayEll64@aol.com
> Reply-To: ti-math@lists.ticalc.org
> To: ti-math@lists.ticalc.org
> Subject: Re: TI-M: TI-89 root question
> Date: Tue, 6 Jun 2000 15:10:37 EDT
> 
> 
> In a message dated 6/6/00 12:38:44 PM Mountain Daylight Time,
> aselle@ticalc.org writes:
> 
>  > Well, you can take a^(1/n) for the nth root of a, but be careful of the
>  >  domain, I forget exactly how the calculator deals with it.
> 
> On my 85, if "a" is non-negative, it returns a real number; usually if "a" 
> is
> negative, it'll return an imaginary number, whether the true root is
> imaginary or not...actually, if you *really* want the nth root*s* of "a",
> you'd use deMoivre's theorem.
> 
> JayEll
> 
> 
> 
> --Robert Mohr--
> rmohr02@hotmail.com
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References:

Re: TI-M: TI-89 root question

From: "Robert Mohr" <rmohr02@hotmail.com>