Re: TI-M: TI-89 root question

To: ti-math@lists.ticalc.org
Subject: Re: TI-M: TI-89 root question
From: "Robert Mohr" <rmohr02@hotmail.com>
Date: Tue, 06 Jun 2000 17:18:24 EDT
Reply-To: ti-math@lists.ticalc.org

I don't know much about the TI-89, but I know how to get the nth root of a 
number on the 86 in a couple of ways.

First, on the TI-86, there's a command that has a little "x" up high in the 
first space, then a radical sign, and then you put the number in.  It should 
look something like this:

                              ___
             \/              /
             /\             /
                   __      /
                     \    /
                      \  /
                       \/

You put 3 in fromt of that and 27 afterwards and it'll return 3.

And before I knew about that, i did this:

27^3(-1)

Note:  the -1 is for inverse, not negative one.

----Original Message Follows----
From: JayEll64@aol.com
Reply-To: ti-math@lists.ticalc.org
To: ti-math@lists.ticalc.org
Subject: Re: TI-M: TI-89 root question
Date: Tue, 6 Jun 2000 15:10:37 EDT

In a message dated 6/6/00 12:38:44 PM Mountain Daylight Time,
aselle@ticalc.org writes:

 > Well, you can take a^(1/n) for the nth root of a, but be careful of the
 >  domain, I forget exactly how the calculator deals with it.

On my 85, if "a" is non-negative, it returns a real number; usually if "a" 
is
negative, it'll return an imaginary number, whether the true root is
imaginary or not...actually, if you *really* want the nth root*s* of "a",
you'd use deMoivre's theorem.

JayEll

--Robert Mohr--
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Re: TI-M: TI-89 root question

From: Andy Selle <aselle@ticalc.org>