Re: i to the ith power


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Re: i to the ith power



That's pretty technical.  You'll probably get the best answer if you ask TI
directly.  ti-cares@ti.com

>Why when I take (a)  sqroot(-1) ^sqroot(-1) or (b) i ^ sqroot(-1) or (c)
>sqroot(-1)^i  the ti-83 gives an undefined response (specifically an error
>message) but when I try i^i  it gives back .2078795764
>How does the ti-83 handle an imaginary raised to an imaginary power?

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