Re: Volume of a 3d figure
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Re: Volume of a 3d figure
Thanks!
--
Matt Weintraub
neda@erols.com
http://www.erols.com/neda
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pucufREMOVE@yahoo.com wrote in message
<36a23979.2832558@news.northcoast.com>...
>You do it just like you do on paper. Integrate in one direction, then
>another. Depending on the function, which variable you integrate with
>respect to can be important.
>
>For example, say you want the area under the "sheet" formed by the
>function z=x^2+y^2 from -5 to 5 on both the x and y directions. To do
>this on paper, you would integrate WRT the x direction, then integrate
>the result WRT Y.
>
>On the calc, it's the same. Just enter (where "S" is the integrate
>operand)
>S(S(x^2+y^2,x,-5,5),y,-5,5)
>
>
>
>On Sat, 16 Jan 1999 00:23:22 -0500, "Matt Weintraub" <neda@erols.com>
>wrote:
>
>>Does anyone know how to find the volume of a 3d graph? Say you wanted to
>>find the volume of a walnut looking solid, how would you do this with the
>>89? I know how to do this via integration and the like using pencil and
>>paper, but I was looking for a shortcut via the 89.
>>Thanks,
>>
>>
>>--
>>
>>Matt Weintraub
>>neda@erols.com
>>http://www.erols.com/neda
>>"Your mouse cursor has moved.
>>NT must be restarted for this change
>>to take effect."
>>
>>
>>
>>
>
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