TI-92 Phasor question (fwd)

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TI-92 Phasor question (fwd)

Well, if your '92 starts buzzing loudly and the screen is flashing red.
It's on overload.  Quick, drop it down the waste chute, hit the eject
"blow into space" button and hit the deck!!!!!!!








A HA HAHAH   I kill myslef sometimes.


*************************************************************************
Charles Slaustas - Comp Sci
CBS@EAGLE.IBC.EDU






***************************************************************************




---------- Forwarded message ----------
Date: Wed, 23 Oct 1996 22:09:50 -0700
From: Randall Vogtman <shamaal@IWL.NET>
To: CALC-TI@LISTS.PPP.TI.COM
Subject: TI-92 Phasor question


Please, no replies referencing Mr.Spock ...


While performing phasor (Steinmetz) calculations with my new TI-92, I've
come across a problem where I don't believe a variable is storing
correctly.
I've sent a question off to ti-cares, but I thought I'd try here also.


i = [2nd] I (imaginary i) not the letter
e = [2nd] LN e(x) (natural logarithm)


First I define b as a -70.0 degree polar phasor value; Enter:


define b=e(-70.0i)


Then I try to examine the variable by entering b; the calculator
returns:


e -25.1576E0i (superscript)


These are not equal.


Calculator Modes:
Complex format - Polar
Angle - Degree
Exact/Approv - Auto


I've tried various combinations of formats and modes and I've discovered
the following parameters:


Exclusion of the decimal point, b=e(-70i), will store correctly, the
decimal point seems to confuse it.


Exclusion of i (imaginary) will cause the calculator to return the
computed value (397.545E-33) which is understandable, although I'd like
to see the e retained, like pi.


Has anyone seen this before and maybe point me in the right direction?


Thanks,


shamaal@iwl.net