Re: A86: Line routines

To: assembly-86@lists.ticalc.org
Subject: Re: A86: Line routines
From: PXGray@aol.com
Date: Sun, 2 May 1999 16:58:04 EDT
Delivered-To: assembly-86-outgoing@towerguard.unix.edu.sollentuna.se
Delivered-To: assembly-86@lists.ticalc.org
Reply-To: assembly-86@lists.ticalc.org


In a message dated 5/2/99 3:54:05 PM US Eastern Standard Time, 
ComAsYuAre@aol.com writes:

> a byte boundary means that (this is for horizontal lines) the entire byte 
is 
>  filled.
>  
>  ex: if you have a small video mem like this:
>  %00000000,%00000000,%00000000,%00000000,%00000000
>  and you want to draw a line, then it wouldn't overlap bytes, so it might 
> show 
>  up like this:
>  %00000000,%11111111,%11111111,%11111111,%00000000
>  whereas a horiontal line that overlapped bytes might be like this:
>  %00001111,%11111111,%11111111,%11100000,%00000000
>  
>  it is much more convenient if they don't overlap bytes.

I still don't understand.  I can send you a screenshot of what I am going to 
be drawing, but I am really in the dark to all this.