Re: A86: Line routines

To: assembly-86@lists.ticalc.org
Subject: Re: A86: Line routines
From: ComAsYuAre@aol.com
Date: Sun, 2 May 1999 16:53:18 EDT
Delivered-To: assembly-86-outgoing@towerguard.unix.edu.sollentuna.se
Delivered-To: assembly-86@lists.ticalc.org
Reply-To: assembly-86@lists.ticalc.org

In a message dated 5/2/99 3:01:16 PM Eastern Daylight Time, PXGray@aol.com 
writes:

> The lines will not move at all, and I have no idea what you mean by a byte 
>  boundary.  Can you comment this, so I know what I am looking at?  Thanks.

a byte boundary means that (this is for horizontal lines) the entire byte is 
filled.

ex: if you have a small video mem like this:
%00000000,%00000000,%00000000,%00000000,%00000000
and you want to draw a line, then it wouldn't overlap bytes, so it might show 
up like this:
%00000000,%11111111,%11111111,%11111111,%00000000
whereas a horiontal line that overlapped bytes might be like this:
%00001111,%11111111,%11111111,%11100000,%00000000

it is much more convenient if they don't overlap bytes.