[A83] Re: Dividing
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[A83] Re: Dividing
Pretty close. I presume you mean rlca when you say "rol", and you shouldn't
need to do any and-ing if it's already 2 bit.
ld ix,here
ld a,l
rlca
rlca
or h
ld (here+2),a
here:
ld a,(ix+0)
ret
.db 0,1,2,3,0,0,1,1,0,0,0,1
In a message dated 6/8/2001 5:41:17 PM Eastern Daylight Time,
lairfight@softhome.net writes:
> lol.. something like this, for h over l:
>
> ld ix,here
> ld a,l
> rol a
> rol a
> and 12
> or h
> ld (here+2),a
> here: ld a,(ix+0)
> ret
>
> .db
----
Jonah Cohen
<ComAsYuAre@aol.com>
http://jonah.ticalc.org