Re: A83: $0D
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Re: A83: $0D
$0D is indeed in hex and = 13 decimal, the only
thing that might sound weird now is that it goes to the next suit if it IS = 13
since there are 13 cards per suit.... the solution is simple, remember
that computer start counting from 0, so 0 to 12 is 13
try it ! 0 1 2 3 4 5 6 7 8 9 10 11 12.... there
!!
-Nicolas Gilles
PS: What's obvious for some, is not obvious for
all...
----- Original Message -----
Sent: Tuesday, February 06, 2001
22:40
Subject: Re: A83: $0D
$0D is 0D in hex, which
IS 13 :-)
Count from 1 to 9, then start at A (10) and move on up to D.
In a message dated 2/6/01 4:38:50 PM Eastern Standard Time,
playnogamz@nls.net writes:
I was reading throught the shuffle routine in Solitare (TI-83
AShell) and
noticed that it compared the current number loaded in a with
$0D after
anding A and 00001111b.
Shuffle:
ld
b,4
;the
number of suits
xor a
;ld
a with 0
ld hl,CARDLIST
CreateListLoop:
ld (hl),a
inc hl
inc a
ld c,a
and %00001111
;don't
look at the suit
\THESE TWO LINES
cp $0D
;when
low nibble is $D, move to next suit
/THESE TWO LINES
ld
a,c
jr nz,CreateListLoop
add a,%00010000
;move
to the next suit (add 1 to high
nibble)
and %11110000
;reset
the low nibble
djnz CreateListLoop
What does $0D
stand for. I thought that it stood for 0 but that whould make
16
cards for each suite, and there should only be 13. Thanks in advance!
----
Jonah Cohen
<ComAsYuAre@aol.com>
http://jonah.ticalc.org
References: