Re: A83: Re: Square root of 0, OT

To: assembly-83@lists.ticalc.org
Subject: Re: A83: Re: Square root of 0, OT
From: Linus Akesson <lairfight@softhome.net>
Date: Sat, 05 Sep 1998 12:52:16 +0100
Delivered-To: assembly-83-outgoing@towerguard.unix.edu.sollentuna.se
In-Reply-To: <48b4cdd5.35f0d8c5@aol.com>
Reply-To: assembly-83@lists.ticalc.org

On 05-Sep-98, JUSTINJS@aol.com wrote:

>ok enuff about deviding by 0 and it square root, what would the square root
of
>Iota be, lodgicaly it should be imposible becouse Iota = the smalest amount
>posible( sqr. root of Iota = ERROR)   what my calc says is .7071067812+.70...
>??????? 

Sigh. If your calculator says .7071067812+.70... then it means that if you
press right, you'll see the rest of the answer. Probably ends with an i.

Linus

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Re: A83: Re: Square root of 0, OT

From: JUSTINJS@aol.com

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