Re: A83: Square root of 0, OT
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Re: A83: Square root of 0, OT
>This is extremely off topic but I figured somebody could tell me here.
>The square root of 0 according to my handy-dandy TI-83 is 0. But, here
>is where I am lost. Wouldn't the below equation rule 0 as non-real?
>
> ___ 2
> / 2 -- X
>\/ X -- ---
> X
>
>If X was zero make this impossible? And if not then how can you prove
>the square root of 0 is 0.
>
>BTW, forgive my ignorance if this something that isn't that complicated.
hmm.. I was a bit tired at my last mail :) but I still dont really get
the question.. anyway the answer tthe equation above is that X is valid
for all Values (hmm.. I dont rally know the mathematical therms in english
:) exept for 0..
couse:
SQR(X^2) = X^2/X => : X != 0 because you cant divide with zero.
=> X= X^2/X =>
=> X=X : X = All possible Real(?) values..
: but the answer X=0 is ruled out by the : original equation
//Olle - sorry if I didn't answer your question ;)
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