Re: A83: Re: Square root of 0, OT
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Re: A83: Re: Square root of 0, OT
I probably should have put it like this...
A * B = C, then C / A = B and C / B = A
In this case it would be more like this though:
A * A = B, then B / A = A
Anyway
0 * 0 = 0, then 0 / 0 = ERROR
And for you who say it equals 0 are wrong:
0 / 1 = 0
because you can never have less that a whole. Anyone here take finite
math?
Scott Dial (Revenant) wrote:
>
> But,
>
> A * B = C, then C / A = B
>
> 0 * 0 = 0, then 0 / 0 = 0
>
> That doesn't work... That is the basis of how they relate to each other
>
> Harper Maddox wrote:
> >
> > Im assuming that the calculator decided to use the wrong properties of math.
> > __
> > since 0*0=0, then wouldnt the \/ 0 be zero too
> >
> > because the square root of a number is equal to a number, which when
> > multiplied by itself equals the original number inside the square root.
> >
> > -Harper Maddox
> >
> > jerky@ebicom.net
> > IRC nick: Geori
> > ICQ: 1214597
> >
> > -----Original Message-----
> > From: Scott Dial (Revenant) <homosapian@geocities.com>
> > To: ASM83 <assembly-83@lists.ticalc.org>
> > Date: Friday, September 04, 1998 10:41 PM
> > Subject: A83: Square root of 0, OT
> >
> > >
> > >This is extremely off topic but I figured somebody could tell me here.
> > >The square root of 0 according to my handy-dandy TI-83 is 0. But, here
> > >is where I am lost. Wouldn't the below equation rule 0 as non-real?
> > >
> > > ___ 2
> > > / 2 -- X
> > >\/ X -- ---
> > > X
> > >
> > >If X was zero make this impossible? And if not then how can you prove
> > >the square root of 0 is 0.
> > >
> > >BTW, forgive my ignorance if this something that isn't that complicated.
> > >
> > >-Revenant
> > >
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