Re: A83: Re: Square root of 0, OT
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Re: A83: Re: Square root of 0, OT
But,
A * B = C, then C / A = B
0 * 0 = 0, then 0 / 0 = 0
That doesn't work... That is the basis of how they relate to each other
Harper Maddox wrote:
>
> Im assuming that the calculator decided to use the wrong properties of math.
> __
> since 0*0=0, then wouldnt the \/ 0 be zero too
>
> because the square root of a number is equal to a number, which when
> multiplied by itself equals the original number inside the square root.
>
> -Harper Maddox
>
> jerky@ebicom.net
> IRC nick: Geori
> ICQ: 1214597
>
> -----Original Message-----
> From: Scott Dial (Revenant) <homosapian@geocities.com>
> To: ASM83 <assembly-83@lists.ticalc.org>
> Date: Friday, September 04, 1998 10:41 PM
> Subject: A83: Square root of 0, OT
>
> >
> >This is extremely off topic but I figured somebody could tell me here.
> >The square root of 0 according to my handy-dandy TI-83 is 0. But, here
> >is where I am lost. Wouldn't the below equation rule 0 as non-real?
> >
> > ___ 2
> > / 2 -- X
> >\/ X -- ---
> > X
> >
> >If X was zero make this impossible? And if not then how can you prove
> >the square root of 0 is 0.
> >
> >BTW, forgive my ignorance if this something that isn't that complicated.
> >
> >-Revenant
> >
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