A83: math poem

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A83: math poem


Not that this has anything whatsoever to do with ti-83 asm programming, it's
just a poem I finished today. Thought you might enjoy it... (this is fun,
hehehee =))

                               THE FINAL PROOF
                              by Linus Akesson


                      We'll first assume that y plus 3
                          Is equal to the letter b

                                    y+3=b

                       Next step would be to multiply
                       Both sides with, say, b minus y

                              (y+3)(b-y)=b(b-y)

                       When this equation's simplified
                       (as much as possible per side)

                              by-y²+3b-3y=b²-by

                       It's clear enough for us to see
                          That if we do subtract 3b

                              by-y²-3y=b²-by-3b

                         It's possible to factorize
                    And soon you won't believe your eyes

                              y(b-y-3)=b(b-y-3)

                        'Cause cancelling the obvious
                     Does leave a startling sight to us:

                                     y=b

                       Since y plus 3's the same as b
                        Then y must be itself plus 3!

                                    y=y+3


Linus
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