Vector Solver v3.0
by Steven Schulze
jlsdvmkids@aol.com

This program was desgined by me because I was so tired of using the law of sines and cosines to solve vectors.

It is pretty simple to use but there are two things that may be confusing so I will just explain it all.
When you run the program it asks you how many vectors you are going to add, or subtract, just enter the number of vectors you need to solve.  It must be a whole number and greater than two.
Second it will ask you for the coefficient of the first vector, for those of you that don't know what this is, i will explain it later.  Next it asks for the angle, this must be in carteisain(spelling?), again for those of you that don't know what this is i will explain later.  Next it asks for the magnitude of the vector, remeber whenever you add, or subtract, two of more vectors the magnitudes must have the same unit, i.e one can't be cm and the other m, both have to be m or both cm.  It will repeat this for the number of vectors you have entered and it will then display the resultant.  The "D" in parenthesis next to magnitude means that it is stored in variable "D" incase you need to do something speacial with it, same with the "E" next to the angle.

Ok, now for some explaining...
for these examples let A = vector A with a magnitude of 5.2 cm and an angle of 35 degrees north of east.  And let B = vector B with a magnitude of 3.7 cm and an anlge of 25 degrees south of west. And let C = vector C with a magnitude of 6.4 cm and an anlge of 15 degrees east of south.

First let me explain carteisian:
In carteisian east is 0 degrees, north is 90, west is 180, and south is 270.  if you were given a problem that had an angle 25 degrees west of north, you would add 25 + 90 and get 115 degrees carteisian.  Again if you had an angle 15 degrees north of west, you would subtract 15 from 180 and get 165 degrees carteisan.  any problem with an anlge norht of east is that angle in carteisan

One problem in a pre-cal book may look like this:
2A+B=?
to solve this you would run the program and enter 2 for the number of vectors.  since vector A is being multiplied by 2 you would enter 2 for the coefficient of vector 1.  Now for the angle, remember it must be in carteisian, and since it is 35 degrees north of east, it is 35 degrees cartiesian so enter 35 for the angle and5.2 for the magnitude.  Now for the second vector, since B does not have anything in front of it, it is actually being multiplied by 1 so enter 1 for the coefficitne, and since it is 25 degrees south of west you do 180 + 25 and get 205 for the angle and 3.7 for the magnitude.  After the calculater finishes calculating it, the resultant is 6.79 cm 40.43 degrees cartesian.

Another problem may be:
3A+2B-C=?
you would run the program, enter 3 for the # of vectors, 3 for the coefficient of vector 1, 35 degrees and 5.2 for the magnitude.  For vector 2 enter 2 for the coefficient, 205 for the angle, and 3.7 for the magnitude.  Now for the last vector you would enter -1 for the coefficitent since it is being multiplied by a -1, and for the angle since it is 15 degrees east of south you would do 270 +15 = 285 degrees cartesian and 6.4 for the magnitude.  After entering all of this you should get 12.79 cm, 69.80 degrees cartesian

If you are using this program for physics, the coefficient will probably always be 1 unless you are subtracting, in which it would be -1, but I added this feature because I am in phycics and pre-cal this year so it helped me in both clases.

Also, I tested it throughly and I am pretty sure it works for every possible situation, if you find a bug please report it to me a jlsdvmkids@aol.com and I will be happy to address it.