TI-M: Re: Equation question for TI-89
[Prev][Next][Index][Thread]
TI-M: Re: Equation question for TI-89
The problem:
-1 = -1A + 3B
3 = 2A - 5B
Multiply the top -1 = -1A + 3B by 2
-2 = -2A + 6B
3 = 2A - 5B
The add to two to gether:
-2 = -2A + 6B
3 = 2A - 5B
____________
1 = 1B
or
1 = B
so
subtract 6 from both sides
-2 = -2A + 6
becomes
-8 = -2A
divide both sides by -2
becomes
4 = A
and
add 5 to both sides
3 = 2A - 5
becomes
8 = 2A
divide both sides by 2
becomes
4 = A
B =1
A = 4
you know this.
----- Original Message -----
From: "BG" <gloverbo@msu.edu>
To: <ti-math@lists.ticalc.org>
Sent: Thursday, September 14, 2000 9:38 PM
Subject: TI-M: Equation question for TI-89
>
> Hi everybody,
>
> I'm new to this list. I have a question that probably has an easy
> answer.
> I am about 50 miles away from my TI-89's manual, so unfortunately I
> can't find my answer there.
>
> PROBLEM: how can I enter a system of equations into my TI-89 and have
> it solve them?
> For instance:
>
> -1 = -1A + 3B
> 3 = 2A - 5B
>
> What do A & B equal?
>
> This is two equations with 2 unknowns. Isn't there a function to solve
> this? Can't I do this with a Matrix? If so, could somebody please tell
> me how to do it on a TI-89? I'm going to need to be able to do it with
> 3 equations and 3 unkowns, also. I have an old Casio that I can do it
> on, but my 89 is a great calculator and I'd like to use it for all my
> needs.
>
> Thanks!
>
> B. G.
>
>
>
References: