TI-M: Re: Equation question for TI-89
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TI-M: Re: Equation question for TI-89
You can always look up the manual at TI's web site....
The 89/92+ have a great built-in linear systems of equation solver, just
enter
solve(eqw1 and eqw2, {varlist})
Using your example, you would type
solve(-1 = -1a + 3b and 3 = 2a-5b, {a,b})
which returns
a=4 and b=1
If you want to do it with matrices, you can use rref(--which finds the
reduced row echelon form--on the standard augmented matrix:
rref( [[-1,3,-1] [2,-5,3]] )
which returns
[[1 0 4]
[0 1 1]]
--Mike
----- Original Message -----
From: "BG" <gloverbo@msu.edu>
To: <ti-math@lists.ticalc.org>
Sent: Thursday, September 14, 2000 10:38 PM
Subject: TI-M: Equation question for TI-89
>
> Hi everybody,
>
> I'm new to this list. I have a question that probably has an easy
> answer.
> I am about 50 miles away from my TI-89's manual, so unfortunately I
> can't find my answer there.
>
> PROBLEM: how can I enter a system of equations into my TI-89 and have
> it solve them?
> For instance:
>
> -1 = -1A + 3B
> 3 = 2A - 5B
>
> What do A & B equal?
>
> This is two equations with 2 unknowns. Isn't there a function to solve
> this? Can't I do this with a Matrix? If so, could somebody please tell
> me how to do it on a TI-89? I'm going to need to be able to do it with
> 3 equations and 3 unkowns, also. I have an old Casio that I can do it
> on, but my 89 is a great calculator and I'd like to use it for all my
> needs.
>
> Thanks!
>
> B. G.
>
>
>
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