Re: TI-M: Integral Question

To: ti-math@lists.ticalc.org
Subject: Re: TI-M: Integral Question
From: Isaiah Lankham <issy@shocking.com>
Date: Thu, 14 Sep 2000 16:38:47 -0700
In-Reply-To: <b6.a8f2b92.26f299ad@aol.com>
Reply-To: ti-math@lists.ticalc.org


JayEll, here's a hint:

To integrate the function exp(x^(1/2)) w.r.t. x, you should do a rather
clever "U-Substitution" before you can use the Integration by Parts
Technique.

Specifically, let u = x^(1/2) and solve for x = u^2 so that dx = 2u du.


Peace, long life, and may a T3 line be with you,

       Isaiah Lankham--CSU, Chico Math Lab Manager

At 17:14 hrs -0400 00.09.14, JayEll64@aol.com wrote:
>Now that we're getting into integration by parts...we're starting to
>integrate by parts...  There was one problem on the "suggested exercises"
>that was stumping me:  the integral of e^sqrt(x) with respect to x.  If
>you're willing to answer it, I'd actually like more of a starting hint rather
>than the full solution, and see if I can go from there ;)
>
>So far I have:
>
>integral(e^sqrt(x) dx) =
>[u = e^sqrt(x); du = e^sqrt(x) * 1/(2sqrt(x))]
>[dv = dx; v = x]
>integral(e^sqrt(x) dx) = x * e^sqrt(x) - integral((x * e^sqrt(x) /
>(2sqrt(x))) dx)
>
>Which doesn't seem to help me much...and further applications of integration
>by parts didn't help too much either (I did get various positive half-powers
>of x times e^sqrt(x), but I'm figuring I need a *negative* single half-power
>(square root) of x...).
>
>Thanks,
>
>JayEll

References:

TI-M: Integral Question

From: JayEll64@aol.com