Re: TI-M: Yet another integral question...


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Re: TI-M: Yet another integral question...




In a message dated 10/3/00 4:07:10 AM W. Europe Daylight Time, 
JayEll64@aol.com writes:

> x(t) = 5*(sin(t) - (t - 2)*cos(t))
>  y(t) = -5 * (cos(t) + (t - 2)*sin(t) - 1)

(find integral of y dx)


fnInt(y, x) = fnInt(y * dx/dt, t)
               = fnInt(-25 * (cos(t) + (t - 2) * sin(t) - 1) * (cos(t) + (t - 
2) * sin(t)), t)

I'm sure you can finish it from here.