TI-M: Re: I think you're a weenie!!!
[Prev][Next][Index][Thread]
TI-M: Re: I think you're a weenie!!!
umm.. dont you start out with different values to begin with? (1/3)x^3 !=
(2/3)x^3... and those different values invalidates the rest of it....
----- Original Message -----
From: "Brandon" <brandon@ez-see.com>
To: "TI-Math" <ti-math@lists.ticalc.org>
Sent: Wednesday, May 17, 2000 8:12 PM
Subject: TI-M: I think you're a weenie!!!
>
> So HA!!! I know I'm spreading false math!!! That's why I do it. Besides
> there is a legal (hopfully!) way to do it. Here's the derivitive type
proof
> I told you about. It's in TI-89 syntax with comments on the logic behind
> each step.
>
> (1/3)x^3+x^2+C=(2/3)x^3+x^2+C
> take the derivitve
> x^2+2x=2x^2+2X
> divide by x
> x+2=2x+2
> cancel the 2's
> x=2x
> divide by x again
> 1=2
>
> There you go. It's all legal (like I said before: hopefully!!!) and it's
> NOT false math.
>
> Mark Hazard
>
>
__________________________________________________
Do You Yahoo!?
Talk to your friends online with Yahoo! Messenger.
http://im.yahoo.com
Follow-Ups:
References: