Re: TI-H: ti linking
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Re: TI-H: ti linking
Sorry bad wording. I meant it sends it out serial, by doing the stuff I
have listed there
>Date: Tue, 14 Jul 1998 07:22:15 -0800 (AKDT)
>To: ti-hardware@lists.ticalc.org
>From: Grant Stockly <gussie@alaska.net>
>Subject: Re: TI-H: ti linking
>Reply-To: ti-hardware@lists.ticalc.org
>
>
>What do you mean, convert it to serial? :) Nothing happens when you
>convert it to parallel. All you do is take the binary number and shove
it
>bit by bit.
>
>>Actually, the software converts it to serial, by testing a bit,
pulling
>>the correct line low, waiting for acknowledgement, then doing the
>>proccess over again
>>
>>>Date: Mon, 13 Jul 1998 09:56:57 -0600 (MDT)
>>>From: Greg Hill <gregh@xmission.com>
>>>To: ti-hardware@lists.ticalc.org
>>>Subject: TI-H: ti linking
>>>Reply-To: ti-hardware@lists.ticalc.org
>>>
>>>
>>>On Mon, 13 Jul 1998, Eric M. Fiterman wrote:
>>>
>>>> Does that mean it uses some kind of MUX to transfer data? Rather
>>>> than a straight serial connection...
>>>>
>>>> I guess that way you keep synchronization with the same clock
>>speeds...
>>>
>>>By MUX you mean a multiplexer, right? No, there isn't any need for
that
>>in
>>>this situation.
>>>
>>>I think what happens (without having looked at the actual ROM
routines)
>>is
>>>the program OUTs a byte to port 7. Something (could be hardware or
>>>software) takes that byte and sends it serially. I don't know if the
>>byte
>>>goes MSB or LSB first, but in any case it does go one bit at a time.
>>>
>>>The connection is async (no clock signal). A calc will transmit a bit
>>and
>>>wait for an ack (ACKnowledge). If it doesn't arrive within a certain
>>>amount of time, the operation times out and an error is returned to
the
>>>user.
>>>
>>>--
>>>Greg Hill
>>>greg-hill@bigfoot.com
>>>www.comports.com/link
>>>
>>>
>>>
>>
>>
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>
>
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