Re: TI-H: ti acceleration
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Julian Svirsky wrote:
>
> Hello
> I am e-mailing about TI acceleration. I have found some problems with
> the available plans.
> 1) I found two different places that say that (C9) or the original
> capacitor is 22pF and 33pF what is the true value ?
> 2) This diagram is either wrong or I am misunderstanding it. Can anyone
> explain please.
> (DIAGRAM 1)
> ===========
> | |
> 0-- |
> \ | |
> \ 1pF 0
> \ |
> 0-- <--- Location, where the old C9 used to be
> |
> ====--C9--0
> (22pF)
> First it's supposed to be a slide switch which are usually 2 position
> switches like this
> (DIAGRAM 2)
> _|_ _|_ <---- slider (only has two positions)
> _ _ _ _ _ _
> | | | | | |
> | | | | | | <---- 3 connectors
>
> On slide switches the slider connects left and middle or right and
> middle connectors as in the (diagram 2) above. So how does the (diagram
> 1) work. I think the schematic should follow the (diagram 3) on the
> bottom. can someone please verify that.
> (DIAGRAM 3)
> _|_ <---- slider (only has two positions)
> _ _ _
> | | |
> | | | <---- 3 connectors
> | | |
> --|-|--------(original capacitor (?pF))--------------|
> | | |
> --|------------------------------------------| |
> | | |
> |-------------(new capacitor (1pF))--------|-----0
> | |
> | <>
> | <----- where
> the original
> |-----<>
> capacitor was
I talked to the guy who wrote the txt file on ticalc a while ago and I
asked the same question. He said that you will still get 1pf capacitive
resistance out of his scematic. I decided to do it with a three-pronged
switch with the exact same layout you have above. It works either way.
References: