[TIB] Re: ti-basic Digest V3 #22
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[TIB] Re: ti-basic Digest V3 #22
On Sun, 6 Apr 2003, "giwrgos giwrgos" wrote:
>
> I use ti-89 basic programming
> In one of my programms I have a list which contains equations.
> e.g. {eq1,eq2,......,eqn}->list1
> how can I convert to to a boolean expression in order to use for solve?
> so we have solve(eq1 and eq2 and .... and eqn,{..})
I bet the '89 has a simpler way to do this, but you should know that
solve(abs(eq1)+abs(eq2)+abs(eq3)+...+abs(eqn)) will give you the
answer you're looking for (in which eq1==eq2==eq3==...==eqn==0).
-Arthur