Re: TIB: [Fwd: Graphing circles, elipses, etc on 82]
[Prev][Next][Index][Thread]
Re: TIB: [Fwd: Graphing circles, elipses, etc on 82]
A better way of graphing it would be:
Y1={1,-1}solved equasion
For example in your two equasions:
9x^2+y^2-2y=80 for Y1
x^2+y^2-10y=0 for Y2
Their respective graphs would be:
Y1={1,-1}3sqrt(9-x^2)+1
Y2={1,-1}sqrt(25-x^2)+5
-Miles Raymond EML: m_rayman@bigfoot.com
ICQ: 13217756 IRC: Killer2 AIM: KilIer2 (kilier2)
http://www.bigfoot.com/~m_rayman/
----- Original Message -----
From: <MathWiz314@aol.com>
To: <ti-basic@lists.ticalc.org>
Sent: Saturday, May 29, 1999 4:08 PM
Subject: Re: TIB: [Fwd: Graphing circles, elipses, etc on 82]
> Solve each of the equations for y on paper. You should get a square root
> with a plus/minus.
>
> In function mode,
>
> Enter the positive version into y1 and the negative version into y2.
>
> Graph the equations. It will graph the top piece, then the bottom piece.
References: