Re: TIB: Bad Graph...
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Re: TIB: Bad Graph...
On Thu, 10 Sep 1998, Brice-Olivier Demory wrote:
> I have: f(x) = sin^2 (x) - 2.sin x - 2
> How to enter it in my TI-85 ?
> When f(x) = 0, x must be around -.82 (i'm sure, I've calculated it)
> and the TI finds -.78... What's wrong ?
I entered y1=(sin x)^2-2.sinx-2 because sin^2 (x) causes an error on my
calc (syntax). Anyway, once you graph it try EVAL, x=-.82. (From the
graph screen/menu, MORE, MORE, F1). My calc said that y=-.003134...
Hope that helps,
Tirla
tirla@dump.net
http://www.dump.net/~tirla/
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