Re: ti-syntax...

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Re: ti-syntax...

One way:
 
Y1=(-3<x)(x<3)(x^3 - 12x + 1)
 
If -3<x, the test operation returns 1 (if not, it returns 0). This way, when the value for x is out of range, the value for y is 0. It's not ideal, but works.
 
You could also set the window...
----- Original Message -----
From: Arthur Labenek
To: CALC-TI@LISTS.PPP.TI.COM
Sent: Saturday, January 20, 2001 8:26 PM
Subject: ti-syntax...

I was wondering how one could set up the restriction in the calc? for it to work correctly ?
 
x^3 - 12x + 1, (-3<x<3)
 
would you write it like this ????????? (below)
 
x^3 - 12x + 1,x,x>-3,x<3  (give input error)?
 
 
-any help would be appreciated
 
thanks.

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