Re: i^7 or up on TI83???

To: CALC-TI@LISTS.PPP.TI.COM
Subject: Re: i^7 or up on TI83???
From: Nathaniel Banks <nathaniel.banks@WMICH.EDU>
Date: Thu, 18 Mar 1999 06:39:36 -0500
Reply-To: Nathaniel Banks <nathaniel.banks@WMICH.EDU>

You could do:
i^mod(n,4)

should give you i^n.

ttyl
-----Original Message-----
From: Kirk Lane <snake64@GEOCITIES.COM>
To: CALC-TI@LISTS.PPP.TI.COM <CALC-TI@LISTS.PPP.TI.COM>
Date: Wednesday, March 17, 1999 9:28 PM
Subject: i^7 or up on TI83???


>All right.  My calc does i to any power from 1 to 6 perfectly fine (i^2
>is -1, i^3 is -i, i^4 is 1, i^5 is i, and i^6 is -1) BUT....i^7
>= -3E-13-i!!! It should be -i! i^101 spits out 4.9E-12+i, but ((i^4)^25)*i
=
>i, like it should!  What is wrong, and is there any program that can do
this
>(take the number, divide it down so that it can be i^2, 3, 4, 5, or 6 and
>that to whatever power to make it i^x...)
>
>Thanks
>
>--
>Kirk Lane
>snake64@geocities.com
>ICQ: 28171652

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