I have an 89.... second year with it.... Studying Trig on College level. Rest of class has 83s. Teacher does not know this calc. but encourages use. (class is calc based) I am attempting to solve trig equations by entering: solve((sin(x))^2)*cos(x)-cos(x)=0,x) the answer given is: X=((2*@n5-1)*pi)/2 Question: What does the @n5 tell me? Walt