Re: Help needed with csolve function on the 92

To: CALC-TI@LISTS.PPP.TI.COM
Subject: Re: Help needed with csolve function on the 92
From: Dennis <dgoetz@VT.EDU>
Date: Sat, 13 Sep 1997 17:59:05 GMT
Organization: Virginia Tech, Blacksburg, Virginia
References: <199709121605.SAA28454@skycorp.skynet.be>
Reply-To: Dennis <dgoetz@VT.EDU>
Xref: paladin.american.edu bit.listserv.calc-ti:16650

On Fri, 12 Sep 1997 18:06:57 +0200, Alexis <Vanpir@SKYNET.BE> wrote:

>
>Hello !
>
>Yesterday I had to solve the following equation :
>(-3+i)x2+(5i-1)x+2=0
>I tried it with the csolve fucntion and all I got was an approximation. I
>thus tried to use the well known quadratic formula within a function
>(-b+/-sqr(b2-4ac)/2a) and I got the exact answer. How is that possible ?
>Doesn't the 92 use this formula to solve that kind of equation ?
>Anyway, I'd like to write a function that would extract the a,b and c from
>a quadratic equation and display the solutions as a list but I can't figure
>how to extract the coefs. Has anyone an idea ?
>
>TIA
>
>Alexis

What exactly did you get for your "approximation"? When I do:
  csolve((-3+i)x^2+(5i-1)x+2=0,x) the Ti-92 spits back:
  x= 1/5 + 2/5*i  or  x=-1+i
I get the same thing when I enter a,b,c into the quadratic formula.
This is using the [2nd][i] for the imaginary number as opposed to just
the normal lower case i... I was wondering what type of numbers you
got back?

Dennis

References:

Help needed with csolve function on the 92

From: Alexis <Vanpir@skynet.be>

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