Re: A89: lsr & lsl

To: assembly-89@lists.ticalc.org
Subject: Re: A89: lsr & lsl
From: Scott Dial <wrath@calc.org>
Date: Fri, 28 Jan 2000 23:17:06 -0500
Organization: ByMe Inc. Technologies \ TCPA
References: <20000123203106.D79ACA404A@towerguard.unix.edu.sollentuna.se> <003101bf65e4$8c4452e0$0201a8c0@sparta.lu.se> <38921070.FB7776C4@txcyber.com>
Reply-To: assembly-89@lists.ticalc.org


lsd (hehe) = Logical Shift in direction d

So, lsl.l d2,d0 will shift d0 to the left d2 times (modulo 64). Logical
shift always moves in a 0 bit.

 move.l #$FFFFFFFF,d0
;d0 = #%1111111111111111111111111111111
 move.l #10,d2
 lsl.l d2,d0
;d0 = #%1111111111111111111111000000000

Eric Greening wrote:
> 
> Could some body please explain to me what exactly lsl and lsr do?
> 
> Like, say I have:
>   lsl.l d2,d0
> What exactly will that do to d0/d2?
> 
> Or I have:
>   lsr.l d2,d0
> What would that do to d0/d2?
> 
> Thanks for the help.  I greatly appreciate it.
> 
> Eric Greening

-- 
Scott "_Wrath_" Dial
wrath@calc.org
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References:

A89: The TI-GCC Library files.....

From: mxpxfifws@yahoo.com

A89: Re: The TI-GCC Library files.....

From: "Niklas Brunlid" <e96nbr@efd.lth.se>

A89: lsr & lsl

From: Eric Greening <littlbit@txcyber.com>

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