Re: A86: _CPOP1OP2

To: assembly-86@lists.ticalc.org
Subject: Re: A86: _CPOP1OP2
From: rabidcow@juno.com
Date: Wed, 13 Oct 1999 09:13:00 -0700
Reply-To: assembly-86@lists.ticalc.org

gosh, you guys are so narrow minded!  it affects both z and c.  hl and de
might point to the byte that differs.  bc & a are destroyed.
if everything else checks out, it compares each byte one at a time using
cp, if the two bytes are not equal it returns immediately with flags left
however cp left them.

-josh

On Mon, 29 Nov 1999 20:09:15 -0600 "Brent Schneider" <brent@calc.org>
writes:
>
>OK... lemme just say this
>
>_cpop1op2 stores the result in the z flag
>
>so if I did _cpop1op2 and they were equal, it would jump to hello in 
>this
>example:
>call _cpop1op2
>jp z,hello
>----- Original Message -----
>From: Ricky Cobb <arcadesdude@hotmail.com>
>To: <assembly-86@lists.ticalc.org>
>Sent: Monday, November 29, 1999 3:42 PM
>Subject: Re: A86: _CPOP1OP2
>
>
>
>but if your cp'ing wouldnt you want to test the carry flag?
>
>Ricky Cobb
>arcadesdude@hotmail.com
>icq# 41440378
>
>
>>From: Cassady Roop <croop@oregontrail.net>
>>Reply-To: assembly-86@lists.ticalc.org
>>To: assembly-86@lists.ticalc.org
>>Subject: Re: A86: _CPOP1OP2
>>Date: Sun, 28 Nov 1999 22:10:26 -0800
>>
>>
>>I would assume OP1.  Normally when there are two arguments, the 
>result
>>is stored into the first.
>>
>>Cassady Roop
>>
>>Jeanne9005@aol.com wrote:
>> >
>> > When I CPOP1OP2, where is the result located?
>> >
>> > Glen
>> > tutorial1.cjb.net
>>
>
>
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