A86: Re: Re: a pretty fast multiply method...
[Prev][Next][Index][Thread]
A86: Re: Re: a pretty fast multiply method...
Well as I said before, you just divide by 4 in the table.
----- Original Message -----
From: <joeknoll@myself.com>
To: <assembly-86@lists.ticalc.org>
Sent: Saturday, November 27, 1999 4:58 PM
Subject: A86: Re: a pretty fast multiply method...
>
> Couldn't exactly tell from how you had written it; but you know that
(A+B)(A+B)/4 - (A-B)(A-B)/4 is the same as ((A+B)(A+B) - (A-B)(A-B))/4 ...
that could save you one division step (haven't seen your code). It's the
power of fractions. Okay, later.
> --Joe
>
> ------------------------------------------------------
> Get free personalized email at http://four11.iname.com
>
References: