Re: A86: Re: mod(op1,op2) == 0
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Re: A86: Re: mod(op1,op2) == 0
Sorry, I guess I need a better Assembly to English translator. Would you
like to try that again for me, a little slower this time?
In a message dated 12/1/99 6:51:16 PM Eastern Standard Time,
kirkmeyer@bigfoot.com writes:
>
> There is a call table to ROM page 5, and on it are contained commands that
> take two arguments, such as GCF, and mod. One of the arguments is in OP1
and
> the other is pushed onto the OP stack. Since there's no documentation,
> you'll just have to keep trying numbers until you find the correct # for
> mod...
>
> ----- Original Message -----
> From: <Jeanne9005@aol.com>
> To: <assembly-86@lists.ticalc.org>
> Sent: Wednesday, December 01, 1999 8:48 AM
> Subject: A86: mod(op1,op2) == 0
>
>
> >
> > How do I do mod(op1,op2) == 0? I have tried many ways, but cannot
> remember
> > how it's done.
> >
> > Glen
> > tutorial1.cjb.net
> >
Glen
tutorial1.cjb.net