Re: A86: Re: Re: Questions

To: assembly-86@lists.ticalc.org
Subject: Re: A86: Re: Re: Questions
From: Chicane <chicane@reninet.com>
Date: Tue, 29 Sep 1998 20:29:22 -0700
Delivered-To: assembly-86-outgoing@towerguard.unix.edu.sollentuna.se
In-Reply-To: <3611A140.312672E9@oregontrail.net>
References: <3.0.1.32.19980929070928.0071f560@reninet.com> <361060D7.AE068C35@oregontrail.net> <002901bdeb5d$0f095e40$67e0e6a5@Sammy.rutgers.edu> <3.0.1.32.19980929141024.0071f74c@reninet.com>
Reply-To: assembly-86@lists.ticalc.org


>So at the fourth byte of a normal basic prog it would be: 00
>and at the fourth byte of a locked basic prog would be:   0029

Not quite. The third byte of a Basic program (right after size bytes) is
the $00.
But the header bytes of a protected program are $8e29. Thus there is one
more header byte in a prot program, and you mush have this byte.
I am working on a way to inc the size of a program. I just need to get some
info on some rom calls.

>Yes?  No?  So this means I have to move everything down a byte to
>edit-lock a program?  What would happen if I left out the 00 and put >in
29 by itself? Probably would not run, but i am not sure.


CHICANE
ICQ: #14727618
chicane on EFNET #ti
Homepage: Under Construction.

References:

Re: A86: Re: Re: Questions

From: Chicane <chicane@reninet.com>

Re: A86: Re: Re: Questions

From: Cassady Roop <croop@oregontrail.net>

A86: Re: Re: Questions

From: "Dux Gregis" <assets@eden.rutgers.edu>

Re: A86: Re: Re: Questions

From: Chicane <chicane@reninet.com>

Re: A86: Re: Re: Questions

From: Cassady Roop <croop@oregontrail.net>