A86: port 0


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A86: port 0




all documentation i've seen on port 0 has said that the byte sent to it is
added to $c0, then multiplied by $0100 to become the pointer to the display
memory.

however, i've found that when i made a prog which sent a value greater than
$3c to port 0, ($76) and used $fc00 as a double buffer, copying the entire
contents of $fc00 to $f600 seemed to make it display.  any ideas why?

port 0 is REALLY confusing!