Re: A86: help w/ new pud

To: assembly-86@lists.ticalc.org
Subject: Re: A86: help w/ new pud
From: David Phillips <electrum@tfs.net>
Date: Wed, 22 Jul 1998 00:55:27 -0500
Delivered-To: assembly-86-outgoing@towerguard.unix.edu.sollentuna.se
In-Reply-To: <27764929.35b5410d@aol.com>
Reply-To: assembly-86@lists.ticalc.org


No, each time you add HL to itself, which is, in effect, HL = HL * 2.  Do
this 4 times, and you get HL = HL * 16.  HL = HL * 2 * 2 * 2 * 2.  Powers
of two.

At 09:31 PM 7/21/98 EDT, you wrote:
>
>>add hl,hl  ; multiply by 2
>>add hl,hl  ; " by 4...
>>add hl,hl  ; " by 8...
>>add hl,hl  ; and by 16
>
>but if you did this adding thing, wouldn't you get 5*HL? or are you adding hl
>together,then loading that into another register, and then adding 2*HL to
>that?
>
>
>
>Glen
>no http:// yet
>

--
David Phillips
mailto:electrum@tfs.net
ICQ: 13811951
AOL/AIM: electrum32

References:

Re: A86: help w/ new pud

From: Jeanne9005@aol.com