Re: A86: base 10 display of hex
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Re: A86: base 10 display of hex
DAA would involve BCD numbers, which I cannot store the population or
money in because of speed.
essentially this code performs this operation on any number X:
HLIX = (16777216*X-16777215);
H %= 10;
i was just wondering if there was a faster way to do it
here's my current code again (input AHL):
> >
> > disp_ahl_deci:
> > push hl
> > pop ix
> > ld h,0
> > ld l,a
> > ld b,$18
> > disp_ahl_loop:
> > add ix,ix
> > adc hl,hl
> > dec lx
> > ld a,h
> > cp $0A
> > jr z,disp_ahl_okay
> > sub $0A
> > ld h,a
> > disp_ahl_okay:
> > djnz disp_ahl_loop
> >
> > ;this is just the division by 10 routine (which is what i need help
> > with). it only outputs one number at a time.
Dux Gregis wrote:
>
> I'm not exactly sure how it would be implemeted, but the daa might be useful.
> Other than that, I don't see much else you can do..
>
> Kirk Meyer wrote:
>
> > yeah, but floating point numbers take three times as many bytes and they
> > are slow (besides, if a wanted that i would use BCD numbers instead).
> >
> >
> > Thanx
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