Re: A86: Division in assembly

Re: A86: Division in assembly

• To: assembly-86@lists.ticalc.org
• Subject: Re: A86: Division in assembly
• From: DEATH <joemama@minot.com>
• Date: Tue, 16 Sep 1997 23:20:11 -0500
• References: <3.0.32.19970916152950.0068a59c@dnc.net> <19970916.224444.14198.0.ariwsi@juno.com>
• Reply-To: assembly-86@lists.ticalc.org

ariwsi@juno.com wrote:
> 
> On Tue, 16 Sep 1997 15:29:51 -0700 DeComPro@dnc.net (David Buttolph)
> writes:
> 
> >Can someone tell me how to divide in z80 assembly, it's not DIV is it?
> 
> The following routine will divide C into HL, storing the quotient
> in HL and the remainder in A:
> 
> Divide:                     ;C = divisor, HL = dividend
>     XOR     A
>     LD      B,$10
> divloop:
>     ADD     HL,HL
>     RLA
>     CP      C
>     JR      C,too_low
>     SUB     C
>     INC     L
> too_low:
>     DJNZ    divloop
>     RET                    ;A = remainder, HL = quotient
>     ; Cycles = 715 - 763

its simpler to use the OPs because then you can display them more easily
(thats probably what he wants to do)

• A86: Division in assembly
• From: DeComPro@dnc.net (David Buttolph)
• Re: A86: Division in assembly
• From: ariwsi@juno.com

• Prev: Re: A86: Reader
• Next: Re: A86: Idea for shell/loader standards...
• Index(es):
  • Main
  • Thread