[A83] Re: help for a routine - ASM Multiplying and dividing shortcut
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[A83] Re: help for a routine - ASM Multiplying and dividing shortcut
Hi!
I'm back from school, thanks for your answers!
Now, my answers :
David Philips> It seems that this routine (_divHLbyA) takes the same
amount of time independently of the value of the two numbers... maybe
I'll use it, because i need speed over size.
Ronald Teune> I want to do (h*256)/e because I want to have the ratio
h/e in a byte, and, because e>h, this ratio is <1, that's why I'm
doing this operation.
David Revelj> I won't use any table for such a "simple" operation, I
mean, it's not like trigonometrics, it's not worth it.
Sebastiaan Roodenburg> In my case, I can afford a precision of 2
units. But it can be useful for other purposes to have a perfect (1
unit) precision.
Brett Shaw> I think that it is what does the rom call _divHLbyA.
Thanks for the explaination !
I think I'll use divHLbyA for the moment, but i'm sure finding the
ratio of two numbers ( a fortiori with a precision of 2 units) can be
done with a trick....
Again, thanks !
guillaume hoffmann
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