[A83] Re: help for a routine

To: <assembly-83@lists.ticalc.org>
Subject: [A83] Re: help for a routine
From: "David Phillips" <david@acz.org>
Date: Mon, 16 Sep 2002 14:26:28 -0500
References: <IHUQWUCZWHBZU73LGLJC8TOXPNKFUT.3d85bc26@leshoffmann@9online>
Reply-To: assembly-83@lists.ticalc.org


guillaume.h@ifrance.com writes:
> Input :
> - h, e
> Output:
> - a=(h*256)/e

I don't see any shortcuts, so this should be the fastest way:

 ld l,0
 ld a,e
 call _divHLbyA

This is the source to _divHLbyA (at least on the 86):

_divHLbyA:
 push bc
 ld c,a
 sub a
 ld b,16
_divHLbyA_loop:
 add hl,hl
 rla
 cp c
 jr c,_divHLbyA_jump
 sub c
 inc l
_divHLbyA_jump:
 djnz _divHLbyA_loop
 pop bc
 ret

-- 
David Phillips <david@acz.org>
http://david.acz.org/

References:

[A83] help for a routine

From: guillaume.h@ifrance.com

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