[A83] Re: (hl) and hl

To: assembly-83@lists.ticalc.org
Subject: [A83] Re: (hl) and hl
From: Peter-Martijn Kuipers <hyper@hbyte.net>
Date: Sat, 9 Feb 2002 23:26:28 +0100 (CET)
In-Reply-To: <F85giBy7rJsreffkoKV0000482c@hotmail.com>
Reply-To: assembly-83@lists.ticalc.org


Yeah, thats right, 
to put it another way:

hl is a register that can contain any number between 0 and 65535

(hl) means the byte in memory that has the address
(between 0 and 65535) that equals the number in hl.

in essence: if hl contains 10000, (hl) will point to byte number 10000,
so "ld (hl), 12" will load 12 into byte number 10000.

--Peter-Martijn

On Sat, 9 Feb 2002, Jimmy Pardey wrote:
> 
> Hello!
> (hl) means to use the memory adress hl, while hl means to just take whatever 
> is stored in hl and use it as a number. So,
> 
> ld hl,a_Defined_Memory_Location_In_The_Header
> ld (hl),1234
> 
> will store 1234 to whatever location a_Defined_Memory_Location_In_The_Header 
> is in the calc's mem. If you don't get it, I understand, and I have not 
> programed for ages now, so someone correct me if I am wrong. I am also not 
> quite concious now, so don't trust me completly.
> 
> 
> >
> >  tWhat is the difference between (hl) and hl? Thanks.
> >
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References:

[A83] Re: (hl) and hl

From: "Jimmy Pardey" <j_pardey@hotmail.com>