[A83] Re: Conditional bcall()ing
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[A83] Re: Conditional bcall()ing
>Well, if I remember well (been on holiday...) I first checked it... But
>could also be that I only looked the (assembled) hex-format. Two's
>complement of 5 is 3...
>
> Henk Poley <><
Yeah, well $ has nothing to do with assembled hex data.
It's TASM operator. $ assembles here to FE or -2. $+5 will be assembled to
3.
Anyway this was already explained by Olle.
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