[A83] again: a ret-problem
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[A83] again: a ret-problem
This a 'simplyfied' (i think you'll find it confusing, but please try to
folow it) code from a program i'm trying to make. Can anybody tell me
what's wrong with it, 'cause it just jumps out of the program (i know it has
something to do with a 'ret', but i can't find what's wrong (btw i really
need it that way (i mean i need to 'call' AND 'jump' (depends on '(state)')
label2)
Main:
...
call label1
.... =>(*)
ld a,1 => simplified !!!!!
ld (state),a
jp label2
...
jp label3
...
label1:
xor a
ld (state),a
ld a,(var)
cp 1
jp z,label2
cp 2
jp z,label3
...
label2:
....
call label4 => i think this is an important call (because you
have a call in a call)
ld a,(state)
jp z,label5
ret => i want him to go back to (*)
label3:
...
the same as label2
label4:
....
ret
label5:
rest of my program