Re: A83: Mysterious Data Increase
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Re: A83: Mysterious Data Increase
I think this is why there's an AsmComp function on the TI-83+ that takes this 2-byte/digit
(or whatever) program and squashes it like DevPac83 and the likes. Can anyone confirm
that?
----- Original Message -----
From: Olle Hedman <oh@hem.passagen.se>
To: <assembly-83@lists.ticalc.org>
Sent: Saturday, February 12, 2000 10:48 AM
Subject: Re: A83: Mysterious Data Increase
>
>
> "Fam. Engelen" wrote:
> > I sort of get it now. The calculator uses 2 hexadecimal digits (thus 2
> > bytes) to store the value of one byte. I understand this now, but I don't
> > think it really makes any sense. This would mean that any data stored in an
> > assembly program would take up exactly double the amount of memory that is
> > theoretically needed! This is, ahem, not awfully efficient, is it? Would
> > there be some trick to store a byte in a byte? Is this, maybe, what squish
> > and the likes do? (never used any of these)
> >
>
> In fact, it takes 3 times the memory needed, because it is copied and translated
> into ram at runtime.
> And yes, translating theese ascii hex to binary data, so 1 byte takes 1 byte,
> is exactly what squish does.
>
> file://Olle
>
>
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