Re: A83: ROMcall reference [83]
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Re: A83: ROMcall reference [83]
> > 002Bh - Sets the memory address described above to zero.
> >
> > ;;;; apparently it doesn't.
>
> ...Yeah, it does :) 'sub a' will subtract A from A, thus making A zero.
> It's a byte smaller than doing 'ld a,0'. Most of the "hobby" programmers
> use 'xor a' instead, but it TI's code, they usually use 'sub a'. If you
> were referring to the memory address, it is the same memory as the
> previous call. On the 83 they're both 913Ch (or so I gather from your
> pasted code), on the 83 Plus they're both 9653h.
>
> -Dan Englender
Okay, sorry... Me acting dumb %-)
1 - 1 = 0
3842 - 3842 = 0
A - A = 0 --> And I, "Math Wonder", didn't see...
Henk Poley
BTW: Totaly off subject, but does somebody know what 'Hilbert space' is.
And can he/she tell me it in a simple way. (Don't ask me what 'math-grade'
I'm in, in Holland we don't work with 'grades', So I don't know...)