Re: A83: calls
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Re: A83: calls
Dammit man, give up. He's right
On Sat, 26 Sep 1998 14:41:55 EDT Jkhum98@aol.com writes:
>
>
>In a message dated 09/26/98 1:29:08 PM, oh@hem.passagen.se writes:
>
>>Its not gonna be a loop because after he calles third label, he rets
>>back to after the call to label and then rets out of the program...
>>
>>go through it again and I'm sure you will find that I am right :)
>>
>>//Olle
>
>Hmm, nope. I see that it will pass through the _Label_ "third_label"
>and carry
>out another "ret", but Go one step further, and after returning from
>the very
>First call, it will then pass through the _Label_ "second_label" and
>once
>again does "call third label". Find, in my lil diagram, the words
>"(second
>return spot)" and then you'll see the little arrow that points down,
>and from
>there That is why a loop is created...
>
> --Jason
>K.
>>> first_label:
>>> call second_label
>>> |--> (second return spot)
>>> | |
>>> | V
>>> | second_label:
>>> | call third_label - |
>>> | |--->(first return spot) |
>>> | | | |
>>> | | V |
>>> | | third_label: <------ |
>>> | |---- ret (first time)
>>> |------ (second time)
>
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