Re: A83: Re: Square root of 0, OT

To: assembly-83@lists.ticalc.org
Subject: Re: A83: Re: Square root of 0, OT
From: JUSTINJS@aol.com
Date: Sat, 5 Sep 1998 16:28:13 EDT
Delivered-To: assembly-83-outgoing@towerguard.unix.edu.sollentuna.se
Reply-To: assembly-83@lists.ticalc.org


In a message dated 9/5/98 8:38:49 AM Pacific Daylight Time,
lairfight@softhome.net writes:

> Subj:	 Re: A83: Re: Square root of 0, OT
>  Date:	9/5/98 8:38:49 AM Pacific Daylight Time
>  From:	lairfight@softhome.net (Linus Akesson)
>  Sender:	owner-assembly-83@lists.ticalc.org
>  Reply-to:	assembly-83@lists.ticalc.org
>  To:	assembly-83@lists.ticalc.org
>  
>  
>  On 05-Sep-98, JUSTINJS@aol.com wrote:
>  
>  >ok enuff about deviding by 0 and it square root, what would the square
root
>  of
>  >Iota be, lodgicaly it should be imposible becouse Iota = the smalest
amount
>  >posible( sqr. root of Iota = ERROR)   what my calc says is
.7071067812+.70..
> .
>  >??????? 
>  
>  Sigh. If your calculator says .7071067812+.70... then it means that if you
>  press right, you'll see the rest of the answer. Probably ends with an i.
ok, yes it did but...
Iota is the smalest # corect? so how could it get smaller?

Follow-Ups:

Re: A83: Re: Square root of 0, OT

From: Linus Akesson <lairfight@softhome.net>

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